G(1-x)=3x^2-4x+8

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Solution for G(1-x)=3x^2-4x+8 equation: 



(1-G)=3G^2-4G+8

We move all terms to the left:

(1-G)-(3G^2-4G+8)=0

We add all the numbers together, and all the variables

(-1G+1)-(3G^2-4G+8)=0

We get rid of parentheses

-3G^2-1G+4G+1-8=0

We add all the numbers together, and all the variables

-3G^2+3G-7=0

a = -3; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·(-3)·(-7)
Δ = -75
Delta is less than zero, so there is no solution for the equation

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